If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4k^2+7k-312=0
a = 4; b = 7; c = -312;
Δ = b2-4ac
Δ = 72-4·4·(-312)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-71}{2*4}=\frac{-78}{8} =-9+3/4 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+71}{2*4}=\frac{64}{8} =8 $
| 3t3-7=74 | | 14+k/3=17 | | 15*9/5+32=a | | 1/x+(x-3)=x-4 | | 9n-4n+18=28 | | 2/3x+2/3x=3 | | 3u^2-35u-12=0 | | 9600=3.14x | | -4/7v=-26 | | 4.5x+3x=61.5 | | 12x+3x+14=76 | | 5n+3n-12=8 | | 60=32+4h | | 12-5(n)=-38 | | 17(x-2)=-32 | | m^2-17=6 | | 15x÷3x-4=14x= | | 0+n=17 | | 13+n=19.8 | | 7-3x2=1 | | 2a-8=4(-5+2a) | | -2r=-47 | | 865.38=40x+(1.5x*10) | | 2(x+5)-3(4+x)-4x=2x=2x-23 | | 2(x+5)-3(4-x)-4x=2x=2x-23 | | 4x^2-4x-50=0 | | 2b-9=95 | | 5(x-4)+2=173 | | -3+5r=-47 | | x^2-21x-1372=0 | | X=(4i²)³ | | 27-9x=2x-6 |